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  • If <img alt="\mathrm{f(x)=\left\{\begin{array}{ccc} -x^2 & , & x \leq 0 \\ 2 & , & x>0 \end{array}\right.}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B

If \mathrm{f(x)=\left\{\begin{array}{ccc} -x^2 & , & x \leq 0 \\ 2 & , & x>0 \end{array}\right.}, then

Option: 1

f(x) is a periodic function


Option: 2

f(x) is an odd function


Option: 3

f(x)  is continuous at x = 0


Option: 4

 f(x)  is continuous at x = 1

 


Answers (1)

best_answer

f(x)  is not continuous at x = 0, so not differentiable at x = 0.

 

Posted by

manish painkra

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