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If y=e^{x+e^{x+\ldots \ldots t o x}} \text {, then } \frac{d y}{d x} \text { is : }

Option: 1

\frac{y}{y+1}


Option: 2

\frac{y}{y-1}


Option: 3

\frac{y}{1-y}


Option: 4

None of these


Answers (1)

best_answer

y = ex+y   log y = x + y

\Rightarrow \frac{1}{y} \frac{d y}{d x}=1+\frac{d y}{d x} \Rightarrow \frac{d y}{d x}=\frac{y}{1-y}

Hence (C) is correct answer.

 

Posted by

Sanket Gandhi

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