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If in the circuit shown, voltmeter reads 100 V then L is:
                         

Option: 1

0.1 H


Option: 2

0.2 H


Option: 3

0.02 H


Option: 4

0.01 H


Answers (1)

best_answer

This is feasible only at resonance,
\mathrm{\therefore \quad 500=\frac{1}{2 \pi \sqrt{\mathrm{LC}}} \text { or } \frac{1}{2 \pi \sqrt{\mathrm{L} \times 10 \times 10^{-6}}}=500 }
On solving, we get \mathrm{\mathrm{L}=0.01 \mathrm{H} }

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Devendra Khairwa

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