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  • If in the expansion of <img alt="\small (1+x)^n, \quad a, b, \quad c" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Csmall%20%281&plus;x%29%5En%2C%20%5Cquad%20a%2C%20b%2C%20%5Cqua

If in the expansion of \small (1+x)^n, \quad a, b, \quad c  are three consecutive coefficients, then n=
 

Option: 1

\frac{a c+a b+b c}{b^2+a c}


Option: 2

\frac{2 a c+a b+b c}{b^2-a c}


Option: 3

\frac{a b+a c}{b^2-a c}


Option: 4

None of these
 


Answers (1)

best_answer

Trick: Here, a={ }^n C_r, b={ }^n C_{r+1} \text { and } c={ }^n C_{r+2}

    Put n=2, r=0, then option (b) holds the condition i.e. n=\frac{2 a c+a b+b c}{b^2-a c}
 

Posted by

Ritika Kankaria

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