Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • If  is an identity in x. Then the value of <img alt="a+4b-c" src="/l

If (a+1)x^2-(2b+3)x+c=0 is an identity in x. Then the value of a+4b-c equals 

Option: 1

-7


Option: 2

0


Option: 3

7


Option: 4

4


Answers (1)

best_answer

For (a+1)x^2-(2b+3)x+c=0 to be identify.

a +1 =0, \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; 2b +3 =0 \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; c=0

a =-1 \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; b=\frac{-3}{2} \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; c=0

So, a+4b-c=-1+4\left ( \frac{-3}{2} \right )-0

                             =-1-6-0

                             =-7      

Posted by

Suraj Bhandari

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Latest Question