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  • If  is odd and  <img alt="\small { }^n C_0<{ }^n C_1<{ }^n C_2 \ldots<{ }^n C_r>{

If \small n is odd and  \small { }^n C_0<{ }^n C_1<{ }^n C_2 \ldots<{ }^n C_r>{ }^n C_{r+1}>{ }^n C_{r+2}>\ldots>{ }^n C_n, then \small r is equal to .......

Option: 1

r=1


Option: 2

r=n+1


Option: 3

r = no value


Option: 4

None of these


Answers (1)

best_answer

\because n\ is\ odd (given)

\because{ }^n C_r  is the greatest among the values

{ }^n C_0,{ }^n C_1,{ }^n C_2, \ldots,{ }^n C_n

\text { where } r=\frac{n-1}{2} \text { or } \frac{n+1}{2}

But only one term { }^n C_r is greater to other, so there is no value of r.

Posted by

Ritika Kankaria

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