Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • If momentum of a body is increased by , then its kinetic energy increases by  <s

If momentum of a body is increased by 20%, then its kinetic energy increases by
 

Option: 1

36 %
 


Option: 2

40 %
 


Option: 3

44 %
 


Option: 4

48 %


Answers (1)

best_answer

\mathrm{\frac{\Delta p}{p} \times 100=20 \%}

\mathrm{p_i=p}

\mathrm{p_f=1.2 p}

\mathrm{K E_i=\frac{p_i^2}{2 m}}

\mathrm{K E_f=\frac{p_f^2}{2 m}}

\mathrm{\frac{K E_F}{K E_i}=\frac{p_f^2}{p_i^2}=\frac{1.44 p^2}{p^2}}

\mathrm{\Delta K E =K E_f-K E_i }

            \mathrm{=0.44\: K E_i }

\mathrm{\frac{\Delta K E}{K E_i} \times 100=44 \%}

The kinetic energy increases by \mathrm{44 \%}

Posted by

manish

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 Live: NTA JEE exam city intimation slip soon at jeemain.nta.nic.in; admit card, updates
anam-khan

JEE Main Passing Marks 2025: Cut-off rises by 3 marks for General; category-wise qualifying scores
anam-khan

JEE Main 2025 Live: NTA session 1 exam city slip soon at jeemain.nta.nic.in; schedule, cut-offs

Latest Question