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If odds against event A are 8 to 3. If only one out of A or B can be selected. Find odds in favor of B. 

Option: 1

3:8


Option: 2

3:11


Option: 3

8:3


Option: 4

8:11


Answers (1)

best_answer

As we learned

Odds in favour and Against an event -

Let S be the sample space and E be an event then odd in favour of E.

- wherein

\frac{n\left ( E \right )}{n\left ( E{}' \right )}= \frac{P\left ( E \right )}{P\left ( E{}' \right )}

and     \frac{n\left ( E{}' \right )}{n\left ( E{} \right )}= \frac{P\left ( E{}' \right )}{P\left ( E{}\right )}     for odd against E

 

 

P(A){}'=\frac{8}{3+8}=\frac{8}{11}\; \; \; \; ;\; \; \; P(A)=\frac{3}{11}

P(A)+P(B)=1\; \; \; Thus\; \; \; P(B)=\frac{8}{11}

So odds in favor =8:3

Posted by

Ritika Kankaria

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