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  • If of a radioactive isotope decays in <img alt="\mathrm{5}" src="https://entrancecorner

If \mathrm{20 \%} of a radioactive isotope decays in \mathrm{5} days, then the amount of the original material left after \mathrm{15} days will be approximately -

Option: 1

\mathrm{20%}


Option: 2

\mathrm{50%}


Option: 3

\mathrm{60%}


Option: 4

None of these 


Answers (1)

best_answer

\mathrm{\text { Since }\ \ m=\frac{m_0}{\sqrt{1-v^2 / c^2}}\ \ \ \ \ \text {, given }\ m=m \text {. }}
On solving we get \mathrm{v=\frac{\sqrt{8}}{3}\ c}
\mathrm{\begin{aligned} & \mathrm{v}=\frac{2 \sqrt{2}}{3}\ \mathrm{c} \\ & \mathrm{v}=\frac{2 \times 1.414 \times 3 \times 10^8}{3} \end{aligned}}
\mathrm{\% \text { value }\ \ \ \ \ \ v=20 \%}
 

Posted by

Deependra Verma

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