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  •  If    of some cell is given as  <img alt="\mathrm{ 0.34 \mathrm{~V}}

 If  \mathrm{ E_0}  of some cell is given as  \mathrm{ 0.34 \mathrm{~V}}  and  \mathrm{ 0.1 \mathrm{M}}  of solution is dipped at  \mathrm{ 25^{\circ} \mathrm{C}} with two electron exchange. Calculate the electrode potential

Option: 1

0.42 V


Option: 2

0.39 V


Option: 3

0.31 V


Option: 4

0.51 V


Answers (1)

best_answer

\mathrm{ E_{\text {cell }}=E_{\text {cell }}^0-\frac{0.0591}{n} \log \frac{[\text { Product }]}{\text { [Reactant] }} }
\mathrm{ n=2 } 
\mathrm{ \text { Ecell } 0.34-\frac{0.0591}{2} \log 10 \\ \ }

\mathrm{ E_{\text {cell }}=0.34-0.03 \\ \ }

\mathrm{ E_{\text {cell }}=0.31 \text { Volts } \ \ }.
 

Posted by

SANGALDEEP SINGH

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