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  • If one end of a diameter of the ellipse <img alt="\mathrm{4 x^2+y^2=16 \text { is }(\sqrt{3}, 2) \text {, }}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B4%20x%5E2&plu

If one end of a diameter of the ellipse \mathrm{4 x^2+y^2=16 \text { is }(\sqrt{3}, 2) \text {, }} 

 then the other end is 

 

Option: 1

\mathrm{(-\sqrt{3}, 2)}


Option: 2

\mathrm{(\sqrt{3},-2)}


Option: 3

\mathrm{(-\sqrt{3},-2)}


Option: 4

\mathrm{(0,0)}


Answers (1)

Since every diameter of an ellipse passes through the centre and is bisected by it, therefore the coordinates of the other end are \mathrm{(-\sqrt{3},-2)} 

Posted by

Kshitij

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