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  •  If origin and are contained in the same angle made by the lines <img alt="\mathrm{2 x+y-a=0, x-3 y+a=0}"

 If origin and (3,2) are contained in the same angle made by the lines \mathrm{2 x+y-a=0, x-3 y+a=0}, then \mathrm{a} must lie in the interval

Option: 1

(-\infty, 0) \cup(8, \infty)


Option: 2

(-\infty, 0) \cup(3, \infty)


Option: 3

(0,3)


Option: 4

(3,8)


Answers (1)

best_answer

If origin and (3,2) are contained in the same angle of

\mathrm{L_{1} \equiv 2 x+y-a=0 \text { and } L_{2} \equiv x-3 y+a=0, \text { then } }

\mathrm{L_{1}(0,0) \cdot L_{1}(3,2)>0 \text { and } L_{2}(0,0) \cdot L_{2}(3,2)>0}

(i.e., both of them must be on the same side of both the lines)

Posted by

Devendra Khairwa

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