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If \mathrm{5 x^2+\lambda y^2=20} represents a rectangular hyperbola, then \mathrm{\lambda } equal 

Option: 1

5


Option: 2

4


Option: 3

-5


Option: 4

None of these


Answers (1)

best_answer

Since the general equation of second degree represents a rectagular hyperbola if \mathrm{\Delta \neq 0, h^2>a b} and coefficient of \mathrm{x^{2}+} coefficient of \mathrm{y^{2}=0}. Therefore the given equation represents a rectangular hyperbola if \mathrm{\lambda+5=0 \text { i.e., } \lambda=-5}

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