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If the centroid of an equilateral triangle is \mathrm{(1,1)} and it's one vertex is \mathrm{(-1,2)}, then the equation of it's circumcircle is

Option: 1

\mathrm{x^2+y^2-2 x-2 y-3=0}


Option: 2

\mathrm{x^2+y^2+2 x-2 y-3=0}


Option: 3

\mathrm{x^2+y^2+2 x+2 y-3=0}


Option: 4

\mathrm{\text { none of these }}


Answers (1)

best_answer

In equilateral triangle circumcentre, centroid, Incentre and orthocentre are on same position.

\mathrm{\text { So radius }=\sqrt{(1+1)^2+(1-2)^2}=\sqrt{5}}

Equation of circle is \mathrm{(x-1)^2+(y-1)^2=5}

Posted by

Gautam harsolia

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