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If the coefficient of the second, third and fourth terms in the expansion of (1+x)^n are in A.P., then n is equal to 
 

Option: 1

7


Option: 2

2


Option: 3

6


Option: 4

None of these


Answers (1)

In the expansion of (1+x)^n, it is given that { }^n C_1,{ }^n C_2,{ }^n C_3 are in A.P.

\begin{aligned} & \Rightarrow 2 \cdot{ }^n C_2={ }^n C_1+{ }^n C_3 \\ & \Rightarrow \quad 2 \cdot \frac{n(n-1)}{1 \cdot 2}=\frac{n}{1}+\frac{n(n-1)(n-2)}{1 \cdot 2 \cdot 3} \\ & \Rightarrow 6(n-1)=6+(n-2)(n-1) \\ & \Rightarrow n^2-9 n+14=0 \Rightarrow n=2 \text { or } n=7 \end{aligned}

But n = 2 is not acceptable because, when n=2, there are only three terms in the expansion of (1+x)^2\therefore n = 7  

Posted by

Ramraj Saini

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