Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • If the conductivity of mercury at <img alt="\mathrm{O^{\circ} \mathrm{C}}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B0%5E%7B%5Ccirc%7D%20%5Cmathrm%7BC%7D%7D" style="height:13

If the conductivity of mercury at \mathrm{O^{\circ} \mathrm{C}}  is  \mathrm{1.36 \times 10^6 \mathrm{sm}^{-1}}and the resistance of a cell containing mercury is  \mathrm{0.428 \Omega}  then constant of cell is

Option: 1

 6.44 


Option: 2

 3.72 


Option: 3

 1.87 
 


Option: 4

 5.82


Answers (1)

best_answer

\mathrm{ K=1.36 \times 10^6 \\ }

\mathrm{ R=0.428 \Omega \\ }

\mathrm{ G=\frac{1}{R}=\frac{1}{0.428} \\ }

\mathrm{ G^*=\frac{K}{G}=\frac{1.36 \times 10^6}{\frac{1}{0.428}} \\ }

\mathrm{ G^*=5.82 }.

Posted by

qnaprep

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026 application correction begins on jeemain.nta.nic.in; edit details by December 2
anam-khan

JEE Mains 2026 LIVE: NTA to conduct session 1 from January 21 to 30; exam pattern, syllabus
anam-khan

JEE Main 2026 correction window opens tomorrow; NTA allows exam city change

Latest Question