Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • If the conductivity of mercury at   is <img alt="1.24 \times 1

If the conductivity of mercury at 0^{\circ} \mathrm{C}  is 1.24 \times 10^6$ ${\mathrm{Sm}^{-1}}  and the resistance of a cell containing mercury is 0.348 \Omega then the cell constant of cell

Option: 1

 316423 
 


Option: 2

824612 


Option: 3

431520 


Option: 4

63264


Answers (1)

best_answer

\mathrm{ K=1.24 \times 10^6 \mathrm{Sm}^{-1} }
\mathrm{ R=0.348 \Omega, G=\frac{1}{R}=\frac{1}{0.348} \\ }

\mathrm{ K=G \times G^* \\ }
\mathrm{ G^*=\frac{K}{G}=\frac{1.24 \times 10^6}{\frac{1}{0.348}} \\ }

\mathrm{ G^*=431520 }
 

Posted by

Divya Prakash Singh

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE 2026: IIT admissions show major shift toward AI, data science, away from core engineering courses
anam-khan

JEE Main 2026: NIT Delhi cut-offs for BTech courses show ever-increasing demands for AI, computer skills
anam-khan

597 Eklavya school students clear JEE, NEET exams in 2024-25; Gujarat, MP lead

Latest Question