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If the distance between the first maxima and fifth minima of a double-slit pattern is 7mm and the slits are separated by 0.15 mm with the screen 50 cm from the slits, then wavelength (in nm) of the light used is

Option: 1

600


Option: 2

525


Option: 3

467


Option: 4

420


Answers (1)

best_answer

Fringe Width is given by

\beta = \frac{\lambda D}{d}
There are  three and a half  fringes from first maxima to the fifth minim as shown,

\Rightarrow \beta = \frac{7mm}{3.5}=2mm\Rightarrow \lambda = \frac{\beta d}{D}= 600nm

Posted by

manish painkra

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