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If the focus of parabola \mathrm{(y-b)^2=8(x-a)} always lies between the line x + y = 2 and x + y = 6, then a + b lies in interval 

 

Option: 1

(0, 2)


Option: 2

(0, 1)


Option: 3

(0, 4)


Option: 4

(1, 4)

 


Answers (1)

best_answer

Co-ordinates of focus will be S(a + 2, b), S lies to the opposite sides of origin w.r.t. line
x + y – 2 = 0 and same side as origin w.r.t line x + y – 6 = 0 hence, 0 < a + b < 4

 

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Devendra Khairwa

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