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  •   If the initial pressure of a gas is 0.03 atm, the mass of the

 

If the initial pressure of a gas is 0.03 atm, the mass of the gas adsorbed per gram of the adsorbent is ______________ \times 10^{-2} \mathrm{~g}

Option: 1

12


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

From Freundlich adsorption isotherm
\begin{aligned} & \mathrm{\frac{x}{m}=k p^{1 / n}} \\ \Rightarrow & \mathrm{\log \left(\frac{x}{m}\right)=\log k+\frac{1}{n} \log p} \end{aligned}

\therefore \mathrm{\log k}=0.602=\log 4

\mathrm{\Rightarrow k=4}

\mathrm{and \: \frac{1}{n}=1 \Rightarrow n=1}

\begin{aligned}\mathrm{ \therefore\left(\frac{x}{m}\right)=4 p =4 \times 0.03} \; \; \; \; \; \\ \; \; =0.12=12 \times 10^{-2} \end{aligned}

Hence,answer is 12

Posted by

sudhir.kumar

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