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  • If the length of the tangent from the origin to the circle with centre <img alt="\mathrm{(2,3)\: is\: 2}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B%282%2C3%29%5C%3A%20is%5C%

If the length of the tangent from the origin to the circle with centre \mathrm{(2,3)\: is\: 2} , then the equation of the circle is
 

Option: 1

\mathrm{(x-2)^2+(y-3)^2=16}
 


Option: 2

\mathrm{(x-2)^2+(y-3)^2=9}
 


Option: 3

\mathrm{x^2+y^2-4 x-6 y=3}
 


Option: 4

None of the these


Answers (1)

best_answer

Let the equation of the circle be \mathrm{x^2+y^2-4 x-6 y+c=0}

\mathrm{\Rightarrow 2=\sqrt{c} \Rightarrow c=4.}

Hence the circle is \mathrm{x^2+y^2-4 x-6 y+4=0}

Hence option 2 is correct.

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mansi

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