If the lines
3y + 4x = 1, y = x + 5 and 5y + bx = 3 are concurrent, then the value of b is
1
3
6
0
Substituting the coordinates of the point of intersection of first two lines, i.e.
(−2, 3) in the third equation, we have 5.3 − 2b = 3 ⇒ b = 6.
Which is given in (c).
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