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  • If the mean deviation of the number 1, 1 + d, 1 + 2d,..., 1 + 100d from their mean is 255 then d is equal to?  Option: 1 10.

If the mean deviation of the number 1, 1 + d, 1 + 2d,..., 1 + 100d from their mean is 255 then d is equal to?

 

Option: 1

10.0


Option: 2

20.0


Option: 3

10.1


Option: 4

20.2


Answers (1)

best_answer

The correct answer is c) 10.1

Given,

\sum_x=101+d(1+25+100)=101+d\left(\frac{100 \times 101}{2}\right)

\mathrm{101 + d(\frac{100\times101}{2})}

\mathrm{\bar{x}=\frac{\sum x}{101}=1+50d}

\mathrm{M.D = \frac{\sum \left | x-\overline{x} \right |}{101}}

\mathrm{225=\frac{50\times 51d}{101}=\frac{2550d}{101}}

\mathrm{101=10d}

\mathrm{d=10.1}



 

 


 

  

 


 

 






 

 

 

 

 

Posted by

avinash.dongre

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