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If the point \mathrm{P\left(a, a^{2}\right)} lies completely inside the triangle formed by the lines \mathrm{x=0, y=0} and \mathrm{x+y=2},then exclusive range of \mathrm{'a'} is

Option: 1

a \in(0,1)


Option: 2

a \in(1, \sqrt{2})


Option: 3

a \in(\sqrt{2}-1, \sqrt{2})


Option: 4

a \in(\sqrt{2}-1,1)


Answers (1)

best_answer

Clearly \mathrm{a \in R^{+}}Also \mathrm{a^{2}+a-2<0}



\mathrm{\Rightarrow(a+2)(a-1)<0}
\mathrm{\Rightarrow-2<a<1}
\mathrm{\Rightarrow a \in(0,1)}

Hence (A) is the correct answer.

Posted by

Ritika Harsh

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