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  • If the radius of the Bohr's orbit of hydrogen atom is <img alt="r_{3}" src="h

If the radius of the 3^{\text {rd }} Bohr's orbit of hydrogen atom is r_{3} and the radius of 4^{\text {th }} Bohr's orbit is \mathrm{r}_{4}. Then :

Option: 1

\mathrm{r}_{4}=\frac{9}{16} \mathrm{r}_{3}


Option: 2

\mathrm{r}_{4}=\frac{16}{9} \mathrm{r}_{3}


Option: 3

r_{4}=\frac{3}{4} r_{3}


Option: 4

r_{4}=\frac{4}{3} r_{3}


Answers (1)

best_answer

Bohr's radius is given as 

\mathrm{r= 0.529\times\frac{n^{2}}{Z}\AA}
where. n = prinicipal quantum number of orbit
            Z = atomic number

\mathrm{r_{3}= 0.529\times \frac{3^{2}}{1} \AA}
\mathrm{r_{4}= 0.529\times \frac{4^{2}}{1} \AA}
\mathrm{\frac{r_{4}}{r_{3}}=\frac{4^{3}}{3^{2}}= \frac{16}{9}\: \: \Rightarrow r_{4}= \frac{16}{9}r_{3}}

Option (2) is correct

Posted by

Ritika Harsh

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