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If the segment intercepted by the parabola \mathrm{y^{2}=4 a x} with the line \mathrm{\mathrm{Ix}+\mathrm{my}+\mathrm{n}=0} subtends a right angle at the vertex, then

Option: 1

\mathrm{4 a m+n=0}


Option: 2

\mathrm{4 \mathrm{am}+4 \mathrm{al}+\mathrm{n}=0}


Option: 3

\mathrm{4 a l+n=0}


Option: 4

\mathrm{al}+\mathrm{n}=0


Answers (1)

best_answer

\mathrm{y^{2}+4 a x\left(\frac{l x+m y}{n}\right)=0}
now coefficient of \mathrm{x^{2}+} coefficient of \mathrm{y^{2}=0 \Rightarrow 4 al +n=0}.

Hence (C) is the correct answer.

Posted by

manish painkra

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