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  • If the sides of a triangle are roots of the equation , then the area

If the sides of a triangle are roots of the equation x^3-4x^2+5x-2=0, then the area of this triangle  

Option: 1

0


Option: 2

\frac{1}{4}


Option: 3

\frac{1}{3}


Option: 4

\frac{1}{2}


Answers (1)

best_answer

\\x^3- 4x^2+5x-2=0\\ (x-2) (x^2-2x+1)=0\\ (x-2) (x-1)^2=0\\ a=2,b=1,c=1\\

As b + c = a, so it is not a triangle and the vertices are lying on a line

So area = 0

Posted by

Devendra Khairwa

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