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If the sum of the coefficients in the expansion of \left(\alpha^2 x^2-2 \alpha x+1\right)^{51} vanishes, then the value of \alpha  is

Option: 1

2


Option: 2

-1


Option: 3

1


Option: 4

-2


Answers (1)

best_answer

The sum of the coefficients of the polynomial \left(\alpha^2 x^2-2 \alpha x+1\right)^{51} is obtained by putting x=1  in \left(\alpha^2 x^2-2 \alpha x+1\right)^{51}

Therefore by hypothesis \left(\alpha^2-2 \alpha+1\right)^{51}=0 \Rightarrow \alpha=1

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Sanket Gandhi

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