Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • If the uncertainty in velocity and position of a minute particle in space are, <img alt="2.4 \times 10^{-26}$ $\left(\mathrm{m} \mathrm{s}^{-1}\right)$ and $10^{-7}(\mathrm{~m})" src="https://entra

If the uncertainty in velocity and position of a minute particle in space are, 2.4 \times 10^{-26}$ $\left(\mathrm{m} \mathrm{s}^{-1}\right)$ and $10^{-7}(\mathrm{~m}) respectively. The mass of the particle in \mathrm{g} is____________.(Nearest integer)
(Given : \mathrm{h}=6.626 \times 10^{-34} \mathrm{Js} )

Option: 1

22


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\text { Uncentainty in velocity }(\Delta \text{V})=2.4 \times 10^{-26} \mathrm{~m/s}

\text { Uncertainty in position }(\Delta \text{x})=10^{-7} \mathrm{~m}

Mass of particle in g = ?

\begin{aligned} \mathrm{\Delta P \cdot \Delta x =\frac{h}{4 \pi} }\\ \mathrm{m \Delta V \cdot \Delta x =\frac{h}{4 \pi}} \end{aligned}

\mathrm{m=\frac{h}{\Delta v \cdot \Delta x \cdot 4 \pi}=\frac{6.626 \times 10^{-34}}{2.4 \times 10^{-26} \times 10^{-7} \times 4 \times 3.14}}

\begin{aligned} &\text{m}=0.02198 \mathrm{~kg} \\ &\text{m}=21.98 \mathrm{~g} \\ &\text{m} \simeq 22 \mathrm{~g} \text { (Nearest integer) } \end{aligned}

Hence, the answer is 22

Posted by

rishi.raj

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025: BTech ECE cut-offs for female candidates go up at top NITs
anam-khan

JEE Main 2025 Session 2 City Slip (OUT) Live: Admit card likely on March 29 at jeemain.nta.nic.in; cut-offs
anam-khan

AESL expands Aakash Digital 2.0 to offer AI-powered coaching for NEET, JEE, Olympiads

Latest Question