Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • If the vertex of a hyperbola bisects the distance between its centre and the corresponding focus, then the ratio of the square of its conjugate axis to the square of its transverse axis is<div

If the vertex of a hyperbola bisects the distance between its centre and the corresponding focus, then the ratio of the square of its conjugate axis to the square of its transverse axis is

Option: 1

3


Option: 2

1


Option: 3

0


Option: 4

-2


Answers (1)

best_answer

Let the hyperbola be\mathrm{\frac{x^2}{a^2}-\frac{y^2}{b^2}=1} Then \mathrm{ 2 a=a c,}i.e.\mathrm{ e=2} Therefore,

\mathrm{ \frac{b^2}{a^2}=e^2-1=3 \quad \text { or } \quad \frac{(2 b)^2}{(2 a)^2}=3}

Posted by

Info Expert 30

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

Amrita BTech Admission 2025: JEE Main-based registration deadline extended to August 30

Latest Question