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If the work function of a metal is 6.63 \times 10^{-19} \mathrm{~J}, the maximum wavelength of the photon required to remove a photoelectron from the metal is ________ nm. (Nearest integer)

\left[\text { Given }: \mathrm{h}=6.63 \times 10^{-34} \mathrm{~J} \mathrm{~s} \text {, and } \mathrm{c}=3 \times 10^{8} \mathrm{~m} \mathrm{~s}^{-1}\right. \text { ] }

Option: 1

300


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

We know,

              \begin{aligned} &\mathrm{\phi=\frac{h c}{\lambda}} \\ &\lambda=\frac{h c}{\phi}=\frac{6.63 \times 10^{-34} \times 3 \times 10^{8}}{6.63 \times 10^{-19}} \mathrm{~m} \\ &\lambda=3 \times 10^{-7} \mathrm{~m} \\ &\lambda=300 \times 10^{-9} \mathrm{~m} \\ &\lambda=300 \mathrm{~nm} \\ \end{aligned}

Answer is 300

Posted by

himanshu.meshram

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