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  • if            then n satisfies the equation :<div class='qna-option'

if            then n satisfies the equation :

Option: 1

n2 + 3n − 108 = 0


Option: 2

n2 + 5n − 84 = 0


Option: 3

n2 + 2n − 80 = 0


Option: 4

n2 + n − 110 = 0


Answers (1)

best_answer

\\\frac{^{n+2} C_{6}}{^{n-2}P_2}=\frac{\frac{(n+2)!}{6!(n+2-6)!}}{\frac{(n-2)!}{(n-2-2)!}} =\frac{(n+2)!}{6!(n-2)!}=11\\\\\Rightarrow \frac{(n+2)(n+1)(n)(n-1)(n-2)!}{(n-2)!}=6!\times11\\\Rightarrow (n+2)(n+1)(n)(n-1)=11\cdot10\cdot9\cdot8\\\Rightarrow n=9

which satisfies the equation n^{2}+3 n-108=0

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manish

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