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  • <img alt="\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6} \xrightarrow[]{\text { Zymase }} \mathrm{A} \xrightarrow[\Delta]{\mathrm{NaOI}} \mathrm{B}+\mathrm{CHI}_{3}" src="/latex-image/?%5Cmathrm%7BC

\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6} \xrightarrow[]{\text { Zymase }} \mathrm{A} \xrightarrow[\Delta]{\mathrm{NaOI}} \mathrm{B}+\mathrm{CHI}_{3}

The number of carbon atoms present in the product B is ____________.

Option: 1

1


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

Zymase converts Glucose into Ethanol and \mathrm{CO_{2}}

So "B" is sodium formate and it contains 1 carbon atom

Hence answer is 1

Posted by

manish

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