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  • <img alt="\mathrm{Pb}\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BPb%7D%5Cleft%28%5Cmathrm%7BCH%7D_%7B3%7D%20%5Cmathrm%7BCOO%7D%5C

\mathrm{Pb}\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2} gives _________ colour with \mathrm{H}_{2} \mathrm{S}.

Option: 1

Orange


Option: 2

Red


Option: 3

Black


Option: 4

White


Answers (1)

best_answer

As we have learnt, 

\mathrm{H_2S} is detected by passing it on Lead acetate paper. It turns black due to the formation of \mathrm{PbS}

\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2} \mathrm{~Pb}+\mathrm{H}_{2} \mathrm{S} \rightarrow 2 \mathrm{CH}_{3} \mathrm{COOH}+\underset{\text { blackppt. }}{\mathrm{PbS} \downarrow}

Hence, the correct answer is Option (3)

Posted by

Nehul

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