Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • <img alt="\mathrm{\text { The value of } \lim _{x \rightarrow \infty} \frac{x^3 \sin (1 / x)-2 x^2}{1+3 x^2} \text { is }}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B%5Ctext%

\mathrm{\text { The value of } \lim _{x \rightarrow \infty} \frac{x^3 \sin (1 / x)-2 x^2}{1+3 x^2} \text { is }}

Option: 1

0


Option: 2

-1 / 3


Option: 3

-1


Option: 4

-2 / 3


Answers (1)

best_answer

The given limit can be re-written as \mathrm{lim _{x \rightarrow \infty} \frac{\frac{\sin (1 / x)}{1 / x}-2}{1 / x^2+3}=-\frac{1}{3} \text {. }}

Posted by

Gaurav

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026: Engineering at NIT Surathkal tougher for insiders, show BTech cut-offs
anam-khan

JEE Main 2026 Registration LIVE: NTA revises session 2 exam dates; application form active for session 1
anam-khan

JEE Main 2026: Wider gap in NIT cut-offs for home and other-state quotas; outsiders need better rank

Latest Question