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In a arrangement, 3n cells of emf \varepsilon and internal resistance r are connected in series. Out of  3n cells, polarity of n cells is reversed. Current in the circuit is

 

Option: 1

\frac{2 \varepsilon}{r}


Option: 2

\frac{2 \varepsilon}{3 r}


Option: 3

\frac{\varepsilon}{3 r}


Option: 4

\frac{\varepsilon}{\mathrm{r}}


Answers (1)

best_answer

E_{effective}=\varepsilon \; \; \; \; \; \; \; r_{effective}=3r

\therefore i=\frac{\varepsilon }{3r}

 

Posted by

Pankaj Sanodiya

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