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  • In a building there are 15 bulbs of 45 W,  15 bulbs of 100 W, 15 small fans of 10 W and 2 heaters of 1 kW. The voltage of the electric main is 220V. The minimum fuse capacity (rated value) of the building will be: (answer in amperes)<b

In a building there are 15 bulbs of 45 W,  15 bulbs of 100 W, 15 small fans of 10 W and 2 heaters of 1 kW. The voltage of the electric main is 220V. The minimum fuse capacity (rated value) of the building will be: (answer in amperes)
Option: 1 20
Option: 2 15
Option: 3 10
Option: 4 25
 

Answers (1)

best_answer

 

 

Total\ power=15\times45+15\times100+15\times10+2\times1000=4325W

Power =VI

So current

I=\frac{P}{V}=\frac{4325}{220}=19.65A

Minimum fuse current should be 20A.

Hence the correct option is (1).

Posted by

Ritika Jonwal

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