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In a metre bridge experiment null point is obtained at 40 cm from one end of the wire when resistance X is balanced against another resistance Y. If X<Y, then the new position (in cm) of the null point from the same end, if one decised to balance a resistance of 3X against Y, will be close to : (in cm) 

Option: 1

67


Option: 2

75


Option: 3

80


Option: 4

50 


Answers (1)

 

 

 

We have from meter bridge experiment

\frac{R_{1}}{R_{2}}=\frac{l_{1}}{l_{2}}$ where $l_{2}=\left(100-l_{1} \mathrm{cm}\right)

In the first case,  \frac{X}{Y}=\frac{20}{80}

\begin{array}{l}{\text { In the second case, } \frac{3 X}{Y}=\frac{l}{100-l}} \\ {l=67 \mathrm{cm}}\end{array}

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Kshitij

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