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In a parallel plate capacitance c, the plate A carries a positive charge and the plate B carries a negative charge. The potential difference between the plates is  v_0 . If the plate A  is given an additional charge +Q , the potential difference between the plates?

Option: 1

V_0-\frac{Q}{2 c}


Option: 2

V_0-\frac{Q}{C}


Option: 3

V_0+\frac{Q}{2 c}


Option: 4

2 V-\frac{Q}{C}


Answers (1)

best_answer

when charge is given to the plate  A, then charge appear on its one face, will be Q/2 therefore  ,

V=V_0+\frac{Q / 2}{C}=V_0+\frac{Q}{2 C}.

Posted by

Rishabh

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