Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • In a parallel plate capacitance , the plate <img alt="\mathrm{A}" src="https://entrancecorne

In a parallel plate capacitance \mathrm{C}, the plate \mathrm{A} carries a positve charge and the plate \mathrm{B} carries a negative charge . The potential difference between the plates is\mathrm{V_{0}} . If the plate \mathrm{A} is given an additional charge \mathrm{\epsilon Q} , the potential difference between the plates ? 

Option: 1

\mathrm{V_{0}-\frac{Q}{2C}}


Option: 2

\mathrm{V_{0}-\frac{Q}{C}}


Option: 3

\mathrm{V_{0}+\frac{Q}{2C}}


Option: 4

\mathrm{2V-\frac{Q}{C}}


Answers (1)

When charge is given to the plate \mathrm{A}, then charge appear on its one face, will be \mathrm{\frac{q}{2}}therefore \mathrm{V=V_{0}+\frac{\frac{q}{2}}{C}=V_{0}+\frac{Q}{2C}}

Posted by

Kshitij

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026 application correction begins on jeemain.nta.nic.in; edit details by December 2
anam-khan

JEE Mains 2026 LIVE: NTA to conduct session 1 from January 21 to 30; exam pattern, syllabus
anam-khan

JEE Main 2026 correction window opens tomorrow; NTA allows exam city change

Latest Question