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  • In a photoelectric experiment, increasing the intensity of incident light :  Option: 1 Increases the number of photons incident and also increases the K.E. of the ejected electrons.  Option: 2 Increa

In a photoelectric experiment, increasing the intensity of incident light :

 
Option: 1 Increases the number of photons incident and also increases the K.E. of the ejected electrons.
 
Option: 2 Increases the frequency of photons incident and increases the K.E. of the ejected electrons.
 
Option: 3 Increases the number of photons incident and the K.E. of the ejected electrons remains unchanged.
 
Option: 4 Increases the frequency of photons incident and the K.E. of the ejected electrons remains unchanged.

Answers (1)

best_answer

Intensity\, of\, light= \frac{N\left ( hf \right )}{At}= \frac{Energy}{At}
Intensity\, of\, light\: \; \alpha\: \: No.\, of\, photons
hf \rightarrow Energy of photon
 N \rightarrow No.of photons
With increase in intensity of light i.e.,  no.of photons there is no change in the energy of photon
\therefore KE of the ejected electron do not increases .
The correct option is (3)

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vishal kumar

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