In a race, there are 8 male participants and 4 female participants. In how many ways can the gold, silver, and bronze medals be awarded if at least one medal must be won by a female participant?
1,008 ways
172,864 ways.
4,032 ways
8,064 ways
To solve this, we will consider the different possible cases based on the number of medals won by female participants:
Case 1: One medal won by a female participant:
Choose 1 female participant for the gold medal (4 choices).
Choose 1 male participant for the silver medal (8 choices).
Choose 1 male participant for the bronze medal (7 choices).
The remaining 6 male participants can be assigned in 6! ways (6 factorial).
Case 2: Two medals won by female participants:
Choose 2 female participants for the gold and silver medals (4 choices for the gold, 3 choices for the silver).
Choose 1 male participant for the bronze medal (8 choices).
The remaining 5 male participants can be assigned in 5! ways.
Case 3: Three medals won by female participants:
Choose 3 female participants for the gold, silver, and bronze medals (4 choices for each medal).
To find the total number of ways, we sum the possibilities for each case:
Case 1: 4 choices × 8 choices × 7 choices × 6! = 4 × 8 × 7 × 720 = 161,280 ways
Case 2: 4 choices × 3 choices × 8 choices × 5! = 4 × 3 × 8 × 120 = 11,520 ways
Case 3: 4 choices × 4 choices × 4 choices = 64 ways
Total: 161,280 + 11,520 + 64 = 172,864 ways.
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