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In a Young's double slits experiment, the ratio of amplitude of light coming from slits is 2 : 1. The ratio of the maximum to minimum intensity in the interference pattern is :
 

Option: 1

9 : 1 


Option: 2

9 : 4 


Option: 3

2 : 1 


Option: 4

25 : 9


Answers (1)

best_answer

Given that

\begin{aligned} & \frac{A_1}{A_2}=\frac{2}{1} \\ & \frac{I_{\max }}{I_{\min }}=\frac{\left(A_1+A_2\right)^2}{\left(A_1-A_2\right)^2}=\frac{9}{1} \\ & =9: 1 \end{aligned}

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Suraj Bhandari

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