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  • In an ellipse the distance between its foci is  and its minor axis is <img alt="8" src="https://entrancecorner.

In an ellipse the distance between its foci is 6 and its minor axis is 8 Then its eccentricity is 

Option: 1

\frac{4}{5}


Option: 2

\frac{1}{\sqrt{52}}


Option: 3

\frac{3}{5}


Option: 4

\frac{1}{2}


Answers (1)

best_answer

Distance between foci\mathrm{=6 \Rightarrow 2 a e=6 \Rightarrow a e=3},Minor axis \mathrm{=8 \Rightarrow 2 b=8 \Rightarrow b=4 \Rightarrow b^2=16} 
from 
\mathrm{b^2=a^2\left(1-e^2\right), \Rightarrow 16=a^2-a^2 e^2 \Rightarrow a^2-9=16 \Rightarrow a=5}
\mathrm{\text { Hence, } a e=3 \Rightarrow e=\frac{3}{5}}
 

Posted by

Suraj Bhandari

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