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 In an experiment a sphere of aluminium of mass 0.20 kg is heated upto 1500C. Immediately, it is put into water of volume 150 cc at 270C kept in a calorimeter of water equivalent to 0.025 kg.  Final temperature of the system is 400C.  The specific heat of aluminium is : (take 4.2 Joule=1 calorie)
Option: 1 378 J/kg – 0C
Option: 2  315 J/kg – 0C
Option: 3  476 J/kg – 0C  
Option: 4  434 J/kg – 0C  
 

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\\ \text{Heat lost by metal Blodg} = \text{Heat gain by} \mathrm{H}_2 \mathrm{O}+ \text{contain} \\ \begin{aligned} &\Rightarrow \mathrm{m}_1 \mathrm{C}_1 \Delta \mathrm{T}_1=\left(\mathrm{m}_2+\mathrm{w}\right) \mathrm{C}_2 \Delta \mathrm{T}_2 \\ &\Rightarrow 0.20 \times \mathrm{C}_1 \times(150-40)=\left(150 \times 10^{-3}\right) \\ &\mathrm{C}_1=434 \mathrm{y} \mathrm{kg}^{-1} \mathrm{k}^{-1} \end{aligned}

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