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In an experiment according to set up, when E1 = 12 volt and internal resistance zero, E = 2 volt. The galvanometer reads zero, then X would be

Option: 1

200


Option: 2

500


Option: 3

100


Option: 4

10


Answers (1)

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Voltage across \mathrm{X} is 2 \mathrm{~V}
\begin{aligned} & \text { So }\left(\frac{E_1}{500+X}\right) X=2 \\ & \Rightarrow\left(\frac{12}{500+X}\right) X=2 \\ & \Rightarrow 12 X=1000+2 X \\ & \Rightarrow 10 X=1000 \quad X=100 \Omega \end{aligned}

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