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In an experiment with sonometer when a mass of 180 g is attached to the string, it vibrates with fundamental frequency of 30 Hz. When a mass m is attached, the string vibrates with fundamental frequency of 50 Hz. The value of m is _______ g.

Option: 1

500


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\begin{aligned} & \mathrm{f}=\frac{1}{2 \ell} \sqrt{\frac{T}{\mu}} \\ & \frac{\mathrm{f}_2}{\mathrm{f}_1}=\sqrt{\frac{T_2}{T_1}} \\ & \left(\frac{50}{30}\right)^2=\frac{\mathrm{mg}}{180 \mathrm{~g}} \\ & \mathrm{~m}=\frac{25}{9} \times 180=500 \mathrm{gram} \end{aligned}

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Shailly goel

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