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In an LCR circuit, the capacitance is made one-fourth, when in resonance. Then What should be change in inductance, so that the circuit remains in resonance?

Option: 1

4 times


Option: 2

\mathrm {1 / 4 \text { times } }


Option: 3

8 times


Option: 4

2 times


Answers (1)

best_answer

The resonant frequency is given by
\mathrm{f_0=\frac{1}{2 \pi} \times \frac{1}{\sqrt{L C}} }
For the circuit to be in resonance LC should be constant. When capacitance is made ¼ of its value, the value of L should be increased four times.

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rishi.raj

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