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In an LR series AC circuit the angular frequency of applied emf is \mathrm{2 \times 10^4 \mathrm{rads}^{-1}} and the value of resistance is \mathrm{10\Omega }. The instant instant at which the value of emf is maximum \mathrm{\mathrm{E}_v } ,the value of current is \mathrm{\frac{i_{\max }}{\sqrt{2}}} .The inductance in the circuit will  be

Option: 1

1 mH


Option: 2

40 mH


Option: 3

8 mH


Option: 4

cannot be predicted


Answers (1)

best_answer

\mathrm{\phi=\pi / 2-\pi / 4=\pi / 4, \tan \pi / 4=1=\frac{L \theta}{R} \therefore L=1 \mathrm{mH}}

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Gunjita

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