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In any given year, the propabality of an earthquake greater than magnitude 6 occuring in the Garhwal Himalayas is 0.04 . The average time between successive occurance of such earthquake in years.

Option: 1

25


Option: 2

-


Option: 3

-


Option: 4

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Answers (1)

Given
\mathrm{P=0.04=\frac{4}{100}=\frac{1}{25} / \text { year }}
i.e., chance of getting an earthquake in a year
\mathrm{=\frac{1}{25}}

So average waiting time = 25 years.

Posted by

Kshitij

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